2x^2-21x+8=0

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Solution for 2x^2-21x+8=0 equation: 



2x^2-21x+8=0

a = 2; b = -21; c = +8;
Δ = b2-4ac
Δ = -212-4·2·8
Δ = 377
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{377}}{2*2}=\frac{21-\sqrt{377}}{4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{377}}{2*2}=\frac{21+\sqrt{377}}{4}
$

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